150=2h^2+10h

Solution for 150=2h^2+10h equation:

150=2h^2+10h

We move all terms to the left:

150-(2h^2+10h)=0

We get rid of parentheses

-2h^2-10h+150=0

a = -2; b = -10; c = +150;
Δ = b2-4ac
Δ = -102-4·(-2)·150
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{13}}{2*-2}=\frac{10-10\sqrt{13}}{-4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{13}}{2*-2}=\frac{10+10\sqrt{13}}{-4}
$